In one of my tables i store my advertisement data, thats one row per advertisement. I also store some dates in an other table, but that's one row per date because i don't know howmany dates a specific advertisement gets. I want to select al the dates (where ID adventisement = 1) in the same query as the data selection, seperated bij a komma. Only problem is that i get as many rows as there are dates, i only want one row with al the data…..
Table 1 (Advertisements)
ID_adv data 1 data2
1 name1 picture1
2 name2 picture2
3 name3 picture3
4 name4 picture4
Table 2 (Dates)
ID ID_adv date
1 2 1-1-2012
2 2 2-1-2012
3 3 1-1-2012
4 3 2-1-2012
5 3 3-1-2012
6 3 4-1-2012
Outcome query (Select ID_adv, data1, data2, dates WHERE ID_adv = 3)
3,name3,picture3,"1-1-2012,2-1-2012,3-1-2012,4-1-2012"
The dates column can be one string with al the dates seperated by a comma….
Any ideas?
You can use GROUP_CONCAT() and GROUP BY to get the results you desire:
SELECT t1.*, GROUP_CONCAT(t2.date) AS dates
FROM Table1 t1
LEFT JOIN Table2 t2
ON t2.ID_adv = t1.ID_adv
GROUP BY t1.ID_adv
This returns all the dates for each advertisement, concatenated by commas. Where there are no dates in Table2 for a particular advertisment, you'll get NULL for the dates column.
To target a particular advertisement, simply add the WHERE clause:
SELECT t1.*, GROUP_CONCAT(t2.date) AS dates
FROM Table1 t1
LEFT JOIN Table2 t2
ON t2.ID_adv = t1.ID_adv
WHERE t1.ID_adv = 3
GROUP BY t1.ID_adv
You can turn rows into a column with GROUP_CONCAT function